4x^2-22x+28=0

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Solution for 4x^2-22x+28=0 equation: 



4x^2-22x+28=0

a = 4; b = -22; c = +28;
Δ = b2-4ac
Δ = -222-4·4·28
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-6}{2*4}=\frac{16}{8}
=2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+6}{2*4}=\frac{28}{8}
=3+1/2
$

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